题解 | #字符串的反码#

#include <stdio.h>
#include <string.h>
int main(){
    char text[81] = {0};
    gets(text);
    int len = strlen(text);
    char reverse[len];
    for (int i = 0; i < len; ++i) {
        if (text[i] >= 97 && text[i] <= 122){
            printf("%c", 122 - (text[i] - 97));
        }
        else if (text[i] >= 'A' && text[i] <= 'Z'){
            printf("%c", 90 - (text[i] - 65));
        }
        else{
            printf("%c", text[i]);
        }
    }
    return 0;
}