题解 | 斗兽棋

题干解读:要求对于输入s1,s2的内容进行比较，分情况输出win,lose和tie

思路：发现s1和s2的内容中首字母都不同，故可直接用首字母来代表不同的棋子，根据首字母的值来输出结果.

#include <iostream>
#include <string>
using namespace std;
int main() {
    string s1, s2;
    cin >> s1 >> s2;
    if (s1[0] == 'e') {
        if (s2[0] == 't') {
            cout << "win";
        } else if (s2[0] == 'm') {
            cout << "lose";
        } else {
            cout << "tie";
        }
    } else if (s1[0] == 't') {
        if (s2[0] == 'c') {
            cout << "win";
        } else if (s2[0] == 'e') {
            cout << "lose";
        } else {
            cout << "tie";
        }
    } else if (s1[0] == 'c') {
        if (s2[0] == 'm') {
            cout << "win";
        } else if (s2[0] == 't') {
            cout << "lose";
        } else {
            cout << "tie";
        }
    } else if (s1[0] == 'm') {
        if (s2[0] == 'e') {
            cout << "win";
        } else if (s2[0] == 'c') {
            cout << "lose";
        } else {
            cout << "tie";
        }
    }
}