with
c as (
select
a.dept_no,
a.emp_no,
b.salary,
rank() over (
partition by
a.dept_no
order by
b.salary desc
) as ranking
from
dept_emp a
join salaries b using (emp_no)
)
select
dept_no,
emp_no,
salary
from
c c
where
ranking = 1
order by
dept_no asc

京公网安备 11010502036488号