题解 | #计算日期到天数转换#

#include <iostream>
using namespace std;
int GetMonthDay(int year,int month)
{
    int MonthDay[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
    if(month==2 && ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)))
    {
        return 29;
    }
    else 
    {
    return MonthDay[month];
    }
}
int main()
{
    int a,b,c;
    while(cin>> a >> b >> c)
    {
        if(b==1)
        {
            cout<<c<<endl;
        }
        else 
        {
        int sum=0;
        while(b>1)
        {
            int d=b-1;
            sum+=GetMonthDay(a,d);
            b--;
        }
        sum+=c;
        cout<<sum<<endl;
        }
    }
    return 0;
}