题解 | 二进制不同位数

#include <stdio.h>

int count1bits(int x) {
    int count = 0;
    for (int i = 0; i < 32; ++i) {
        if (x & (1 << i)) {
            ++count;
        }
    }
    return count;
}

int main() {
    int m, n;
    scanf("%d %d", &m, &n);
    printf("%d\n", count1bits(m ^ n));
    return 0;
}