题解 | 日期类

#include<stdio.h>
using namespace std;

void nextday(int& year, int& month, int& day) {
    int dayofmonth[] = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
    //先判断是否闰年，闰年的2月是29天
    if ((year % 400 == 0) || (year % 100 != 0 && year % 4 == 0))dayofmonth[2] = 29;
    //如果天数超出
    if ((day + 1) > dayofmonth[month]) {
        //如果月份超出
        if ((month + 1) > 12) {
            year++;
            month = 1;
            day = 1;
        } else {
            month++;
            day = 1;

        }

    } else day++;
}

int main(){
    int n=0;
    int curyear,curmonth,curday;
    scanf("%d\n",&n);
    while(n--){
         scanf("%d %d %d",&curyear,&curmonth,&curday);
         nextday(curyear,curmonth,curday);
         printf("%04d-%02d-%02d\n",curyear,curmonth,curday);

    }
   
return 0;

}