题目大意：输入一个数n，再输入一段长度为n只含01的字符串，然后输入n个数，如果该数对应字符串中为1，把这个数加到sum中，然后根据范围输出相应结果

思路：直接上码

代码如下：

#include<stdio.h>
int main()
{
	char a[20000];
	int s[20000],n,i,t,sum,year,cnt;
	scanf("%d",&t);
	while(t--)
	{
		scanf("%d %s",&n,a);
		sum=year=cnt=0;
		for(i=0;i<n;i++)
		{
			scanf("%d",&s[i]);
			if(a[i]=='1')
				sum+=s[i],cnt++;
		}
		if(sum==0) year=0;
		else if(sum<20) year=3;
		else if(sum<30) year=5;
		else if(sum<40) year=10;
		else if(sum<50) year=15;
		else if(sum<60) year=20;
		else if(sum<70) year=25;
		else if(sum<80) year=30;
		else if(sum<90) year=35;
		else year=40;
		printf("Samuel was accused with %d case(s),and he will stay in the prison for %d year(s).\n",cnt,year);
	}
	return 0;
}