题解 | #序列求和#

主要考察遍历和字符类型转换

#include<iostream>
using namespace std;
int main(){
    string s;
    cin>>s;
    int sum = 0;
    for (int i = 0; i<s.length(); i++) {
        sum = sum + s[i]-'0';
    }
    cout << sum << endl;
    return 0;
}