题解 | 凯撒加密

#include <iostream>
#include <string>
using namespace std;

int main() {
    int n;
    cin >> n;
    string s;
    cin >> s;
    int num = s.size();
    char temp;
    while(true){
        if(n >= 0 && n <= 26) break;
        n = n - 26;
    }
    
    for(int i = 0;i < num;i++){
        if(s[i] >= 'a' && s[i] <= 'z'){
            int temp = int(s[i] + n);
            if(temp > 122){
                s[i] = s[i] + (n - 26);
            } else {
                s[i] = s[i] + n;
            }
            
        }
    }
    cout << s;



}
// 64 位输出请用 printf("%lld")