题解 | #在字符串中找出连续最长的数字串#

import java.util.*;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        // 注意 hasNext 和 hasNextLine 的区别
        // while (in.hasNextInt()) { // 注意 while 处理多个 case
        //     int a = in.nextInt();
        //     int b = in.nextInt();
        //     System.out.println(a + b);
        // }
        while (in.hasNextLine()) {
            String s = in.nextLine();
            char[] cs = s.toCharArray();
            int len = cs.length;
            int max = 0;
            List<String> results = new ArrayList<>();
            String temp = "";
            int count = 1;
            for (int i = 0; i < len; i++) {
                char c = cs[i];
                if (Character.isDigit(c)) {
                    temp += c;
                    if (i < len - 1 && Character.isDigit(cs[i + 1])) {
                        count++;
                    } else {
                        if (max == count) {
                            results.add(temp);
                        } else if (max < count) {
                            results.removeAll(results);
                            max = count;
                            results.add(temp);
                        }
                        count = 1;
                        temp = "";
                    }
                }
            }
            for (int i = 0; i < results.size(); i++) {
                System.out.print(results.get(i));
            }
            System.out.println("," + max);
        }
    }
}