题解 | #字符串合并处理#

#将一个十六进制数转换为四位二进制数
def fun1(x1):
    str1 ='1 2 3 4 5 6 7 8 9'
    if str(x1) in str1:
        x = int(x1)
    elif x1 == 'a' or x1 == 'A':
        x = 10
    elif x1 == 'b' or x1 == 'B':
        x = 11
    elif x1 == 'c' or x1 == 'C':
        x = 12
    elif x1 == 'd' or x1 == 'D':
        x = 13
    elif x1 == 'e' or x1 == 'E':
        x = 14
    elif x1 == 'f' or x1 == 'F':
        x = 15
    temp = [0,0,0,0]
    n = 0
    while x // 2 >= 0 and x != 0:
        temp[-1-n] = x % 2
        x = x // 2
        n = n + 1

    return temp 

#将一个四位二进制数转化为十六进制数
def fun2(temp):
    str1 ='1 2 3 4 5 6 7 8 9'
    x = int(temp[0])*2**3 + int(temp[1])*2**2 + int(temp[2])*2**1 + int(temp[3])*2**0
    num = x
    if str(x) in str1:
        num = x
    elif x == 10:
        num = 'A'
    elif x == 11:
        num = 'B'
    elif x == 12:
        num = 'C'
    elif x == 13:
        num = 'D'
    elif x == 14:
        num = 'E'
    elif x == 15:
        num = 'F'
    return num

while True:
    try:
        #获取一行输入数据
        data = input()
        #获取输入的两个字符串
        str1 = data.split(' ')[0]
        str2 = data.split(' ')[1]
        #将两个字符串合并
        str3 = str1 + str2
        #排序
        #定义空列表用于存放数据
        res = [False]*len(str3)
        #用于存放索引值为偶数的字符
        temp1 = []
        #用于存放索引值为奇数的字符
        temp2 = []
        for k,v in enumerate(str3):
            if k % 2 == 0:
                temp1.append(v)
            else:
                temp2.append(v)
        #分别进行排序
        temp1.sort()
        temp2.sort()

        for k in range(0,len(res)):
            if k % 2 == 0:
                res[k] = temp1[k//2]
            elif (k+1) % 2 == 0:
                res[k] = temp2[(k+1)//2-1]
        #此时res为排序后的列表
        #倒序排列测试
#         A1 = '1 2 3 4 5 6'
#         print(A1[::-1])
        #temp3用于存放输出数据
        temp3 = []
        str1 = '1 2 3 4 5 6 7 8 9'
        str2 = 'a b c d e f A B C D E F'
        for word in res:
            if str(word) in str1 or str(word) in str2:
                #将每个字符转化为四位二进制数
                word1 = fun1(word)
                #将四位二进制数按照比特位翻转
                word2 = word1[::-1]
                #将翻转后的四位二进制数转化为十六进制数
                word3 = fun2(word2)
            else:
                word3 = word
            temp3.append(str(word3))
        print(''.join(temp3))


    except:
        break