题解 | 凯撒解密

class Solution {
public:
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     *
     * 进行凯撒解密
     * @param password string字符串 旺仔哥哥的密码
     * @param n int整型 每个字符加密过程中错位的次数
     * @return string字符串
     */
    string decodeWangzai(string password, int n) {
        // write code here
        n = n%26;
        for (int i = 0;i<password.length();i++){
            if(password[i]<='z'&&password[i]>='a'){
                password[i] = password[i] - n;
                if(password[i]<'a'){
                    password[i] = password[i] +26;
                }
            }
        }
        
        return password;
    }
};