题解 | 识别有效的IP地址和掩码并进行分类统计

import sys

a,b,c,d,e,f,g = 0,0,0,0,0,0,0
z = sys.stdin.read().strip().split('\n')
for y in z:
    try:
        h,i= y.split('~')
        j,k,l,m = h.split('.')
        n,o,p,q = map(int,i.split('.'))
        if 0<= n <= 255 and 0<= o <= 255 and 0<= p <= 255 and 0<= q <= 255 :
            r = bin(n)[2:].zfill(8)
            s = bin(o)[2:].zfill(8)
            t = bin(p)[2:].zfill(8)
            u = bin(q)[2:].zfill(8)
            v = str(r)+str(s)+str(t)+str(u)
        if 0<= int(j) <= 255 and 0<= int(k) <= 255 and 0<= int(l) <= 255 and 0<= int(m) <= 255 :
            if int(j) == 0 or int(j) == 127:
                continue
        else:
            f += 1
            continue
        if all(c in '01' for c in v) and '0' in v and '1' not in v[v.find('0'):]:
            if '0' not in v or '1' not in v :
                f += 1
                continue
        else:
            f += 1 
            continue
        if 1<= int(j) <= 126 :
            a += 1
            if int(j) == 10:
                g += 1
        elif  128<= int(j) <= 191 :
            b += 1
            if int(j) == 172 and int(k) == 16:
                g += 1
        elif  192<= int(j) <= 223 :
            c += 1 
            if int(j) == 192 and int(k) == 168:
                g += 1
        elif  224<= int(j) <= 239 :
            d += 1
        elif  240<= int(j) <= 255 :
            e += 1  
        else:
            pass
        
    except:
        f += 1 
    
print(a,b,c,d,e,f,g,sep=' ')