f = float(input())

# print(f**0.5)

# print()

i = f**(1/3)

#print(i)

# while True:

# if i**3 <f and (i+0.1)3>f: # 存在一个问题，当i3接近f，i正确，当I+0.1接近，i差了0.1

# #print(i)

# break

# else:

# i+=0.01

# print(i**3)

# print((i+0.1)**3)

# if f-i**3 >(i+0.1)**3-f: # 我想用绝对值比较哪个更近一点，取哪个，但是还是心有不妥。毕竟四舍五入

# i = i+0.01

print('{:.1f}'.format(i))

f = float(input()) if f<0: f = -f i = f**(1/3) i = -i else: i = f**(1/3)

print('{:.1f}'.format(i)) # 离大谱，居然骗过去了