遍历一遍字符串，一位一位的比较即可

#include<iostream>

using namespace std;

int main()
{
    string S;
    cin>>S;
    string s1="XiaoQiao";
    string s2="XiaoHuiHui";
    int len1 = s1.length();
    int len2 = s2.length();
    int index1 = 0,index2=0;
    for(int i = 0 ; i < S.length();i++)
    {
        if(S[i]==s1[index1]&&index1<len1)
        {
            index1++;
        }
        if(S[i]==s2[index2]&&index2<len2)
        {
            index2++;
        }
    }
    if(index1==len1 && index2==len2)
    {
        cout<<"Happy"<<endl;
    }
    else{
        cout<<"emm"<<endl;
    }
    return 0;
}