切记树状数组不能处理为0的情况(lowbit无法计算,所以遇到这种情况别忘了+1)
#include<cstdio>
#include<iostream>
using namespace std;
int a[500005],b[500005];
int n;
int lowbit(int x)
{
return x&(-x);
}
void add(int x,int y)
{
for(int i=x;i<=n;i+=lowbit(i))
b[i]+=y;
}
int sum(int x)
{
int ans=0;
for(int i=x;i;i-=lowbit(i))
ans+=b[i];
return ans;
}
int main()
{
int m;
scanf("%d%d",&n,&m);
for(int i=1;i<=n;i++)
{
scanf("%d",&a[i]);
add(i,a[i]);//切记初始化!!!
}
char pd;
int x,y;
for(int i=1;i<=m;i++)
{
cin>>pd>>x>>y;
//scanf("%d%d%d",&pd,&x,&y);
if(pd=='x')
{
add(x,y);
}
else
{
printf("%d\n",sum(y)-sum(x-1));//注意不是sum(x,y)
}
}
return 0;
}