select c.name as customer_name ,sum(price) as total_travel_cost ,count(*) as order_count ,round(avg(price),2) as avg_order_price from bookings b join packages p on b.package_id = p.id join customers c on b.customer_id = c.id where year(booking_date) = 2024 group by c.name having sum(price) > 10000 order by total_travel_cost desc



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