题解 | #判断链表中是否有环# 快慢指针

import java.util.*;
/**
 * Definition for singly-linked list.
 * class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) {
 *         val = x;
 *         next = null;
 *     }
 * }
 */
public class Solution {
    public boolean hasCycle(ListNode head) {
        ListNode slow = head;
        ListNode fast = head;
        while (slow != null && fast != null) {
            slow = slow.next;
            fast = fast.next;
            if (fast == null) {
                return false;
            }
            fast = fast.next;
            if (slow == fast) {
                return true;
            }
        }
        return false;
    }
}