题解 | 优雅的点

#include <iostream>
#include "bits/stdc++.h"
using namespace std;

int main() {
    int a, b;
    int r2; 
    float r;
    cin >> r2;
    r = sqrt(r2);

    int x;
    int y;
    int sum = 0;
    for (int x = -floor(r); x <= floor(r); x++) {
        int y = sqrt(r2 - x * x);
        if( (y*y+x*x)  == r2) {
        //if (  y == floor(y) ) {
            if ( abs(x) != r ) {
                sum += 2;
            } else {
                sum ++;
            }
        }
    }
    cout << sum << endl;

}
// 64 位输出请用 printf("%lld")