题解 | #牛牛的金币#

#include<stdio.h>
int main()
{
	int x, y = 0; 
	int x1, y1 = 0;  
	scanf("%d%d%d%d", &x, &y, &x1, &y1); 
	if (x1 - x == 0 && y1 - y == 1)
	{
		printf("u\n");  
	}
	else if (x1 - x == 0 && y1 - y == -1)
	{
		printf("d\n"); 
	}
	else if (x1 - x == 1 && y1 - y == 0)
	{
		printf("r\n");
	}
	else if (x1 - x == -1 && y1 - y == 0)
	{
		printf("l\n");
	}
	return 0;  
}