select
gender, university,
count(device_id) as user_num,
avg(active_days_within_30) as avg_active_day,
avg(question_cnt) as avg_question_cnt
from user_profile
group by gender, university
order by gender;
select
gender, university,
count(device_id) as user_num,
avg(active_days_within_30) as avg_active_day,
avg(question_cnt) as avg_question_cnt
from user_profile
group by gender, university/该子句将 user_profile 表中的数据按照 gender 和 university 的不同组合进行分组。
order by gender;/ORDER BY 子句用于对查询结果进行排序。

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