select music_name
from(
select distinct music_id
from music_likes
where 
user_id in (select follower_id from follow where user_id=1)
and 
music_id not in (select music_id from music_likes where user_id=1)
) as tb1
join music
on tb1.music_id=music.id
order by id

#思路：
#从第二张表中选出被关注者喜欢的音乐id，并且这些音乐id不在关注着自身歌单里；这一步可以做个去重，形成表tb1；
#将tb1和第三张表连接，选出对应的歌名即可。