题解 | 字符串构造判定

#include <unordered_map>
#include <unordered_set>
class Solution {
public:
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     *
     * 
     * @param ransomNote string字符串 
     * @param magazine string字符串 
     * @return bool布尔型
     */
    bool canConstruct(string ransomNote, string magazine) {
        int s1 = ransomNote.size();
        int count = 0;
        unordered_map<char, int> ss;
        for(auto c : magazine){
            ss[c]++;
        }
        int i = 0;
        while (s1) {
            if(ss[ransomNote[i]]!=0){
                count ++;
                ss[ransomNote[i]]--;
            }
            i++;
            s1--;
        }
        if(count == ransomNote.size()){
            return true;
        }else {
            return false;
        }

    }
};