1、先找到元素出现的次数
2、找到大于一般出现的元素
3、找出最大的次数
# -*- coding:utf-8 -*- class Solution: def MoreThanHalfNum_Solution(self, numbers): # write code here count_map = {} numbers_len = len(numbers) for n in range(numbers_len): if numbers[n] not in count_map: count_map[ numbers[n] ] = 1 else: count_map[ numbers[n] ] = count_map[ numbers[n] ] + 1 max_count_map = {} max_flag = '' max_flag_count = 0 print(count_map) for i in count_map.items(): if i[1] >= (numbers_len // 2): print('big than') if max_flag == '': max_flag = i[0] max_flag_count = i[1] print(max_flag) else: if i[1] > max_flag_count: max_flag_count = i[1] max_flag = i[0] print('big than compare') print(max_flag,max_flag_count) return max_flag if __name__ == '__main__': Solution().MoreThanHalfNum_Solution([2,2,2,3,3,3,3])