题解 | #数字之和#

#include <stdio.h>
#include <string.h>

int main() {
  int n,n2;
  while(scanf("%d",&n)!=EOF)
  { int m1=0,m2=0;
       n2=n*n;
    while(n>0)
    {
     m1=m1+n%10;
     n=n/10;
    }
 
    while(n2>0)
    {
     m2=m2+n2%10;
     n2=n2/10;
    }
    printf("%d %d\n",m1,m2);


     
  }
    return 0;
}