先找到salaries表的salary最大值,
然后查找得出除了最大值的子表,
再获取子表的最大值,也就是第二大的值,
然后连接2个表,再通过where查询得到所有salary第二大的员工信息

SELECT 
    emp_no,
    salary,
    last_name,
    first_name
FROM employees
JOIN salaries
USING(emp_no)
WHERE salary =
(
    SELECT MAX(salary)
    FROM(
        SELECT * 
        FROM salaries
        WHERE salary != 
        (
            SELECT MAX(salary)
            FROM salaries
        )
    )
)