题解 | 进制转换

import sys
import math

# hexDict = {
#     '0':0,
#     '1':1,
#     '2':2,
#     '3':3,
#     '4':4,
#     '5':5,
#     '6':6,
#     '7':7,
#     '8':8,
#     '9':9,
#     'A':10,
#     'B':11,
#     'C':12,
#     'D':13,
#     'E':14,
#     'F':15}


# result = 0
# for line in sys.stdin:
#     hexNum = line.split()[0][2:]
#     length = len(hexNum)
#     # print(a[2:])
#     for i in range(length):
#         pos = length - i - 1
#         alpha = hexNum[i]
#         result += math.pow(16, pos) * hexDict[alpha]
# print(int(result)) 
    
s=input()
print(int(s, 16))

虽然靠自己完成了问题，但显然，使用python的朋友一是要会原理二则是要知道有库可以解决问题。