题解 | #记负均正II#

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

static int g_input[50000];
int main(int argc, char** argv)
{
    int num = 0, neg = 0, sum = 0;
    while (scanf("%d", &g_input[num]) != EOF) num++; /* 输入 */
    for (int i = 0; i < num; i++) if (g_input[i] < 0) { neg++; continue; } else sum += g_input[i];/* 统计 */
    if (neg == num) printf("%d\n0.0", neg); else printf("%d\n%.1f", neg, sum / ((float)(num - neg))); /* 结果输出 */
    return 0;
}