题解 | #24点运算#

dic = {'A':1,'2':2,'3':3,'4':4,'5':5,'6':6,'7':7,'8':8,'9':9,'10':10,"J":11,'Q':12,'K':13,'joker':-1,'JOKER':-1}
def func(lst):
    li = []
    for i in lst:
        if dic[i] == -1:
            print('ERROR')
            return
        else:
            li.append(dic[i])
    li_index = []
    for s in range(4):
        for k in range(4):
            if k != s:
                for j in range(4):
                    if j != k and j!= s:
                        for i in range(4):
                            if i!=k and i!=s and i!= j:
                                li_index.append([s,k,j,i])
    li2 = ['+','-','*','/']
    for s in li_index:
        for u in li2:
            for i in li2:
                for o in li2:
                    str1 = f'(({li[s[0]]}{u}{li[s[1]]}){i}{li[s[2]]}){o}{li[s[3]]}'
                    if eval(str1) == 24:
                        str2 = f'{lst[s[0]]}{u}{lst[s[1]]}{i}{lst[s[2]]}{o}{lst[s[3]]}'
                        print(str2)
                        return
    print('NONE')

lst = input().split()
func(lst)