#新简化写法 select t.login_date as dt, count(distinct uid) as total_user_num, concat( ifnull( round( ( count(distinct case when t.m=1 then uid end)/count(distinct uid) )*100,1),0),"%") as new_user_rate from( select uid, login_date, row_number()over(partition by uid order by login_date) as m from user_login_tb group by uid,login_date ) as t group by t.login_date order by t.login_date



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