题解 | #重复的DNA序列#

class Solution {
public:
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     *
     * 
     * @param DNA string字符串 1
     * @return string字符串vector
     */
    vector<string> repeatedDNA(string DNA) {
        // write code here
        unordered_map<string, int> rec;
        string temp;
        for(int i=0; i<=DNA.length()-10; i++){
            temp = DNA.substr(i, 10);
            rec[temp] += 1;
        }
        
        vector<string> res;
        for(int i=0; i<=DNA.length()-10; i++){
            temp = DNA.substr(i, 10);
            if(rec[temp] > 1){
                res.push_back(temp);
            }
            rec.erase(temp);
        }
        return res;
    }
};