public class Solution {
    public void merge(int A[], int m, int B[], int n) {
        // 二分查找然后插入
        for(int i=0;i<n;i++){
            int val = B[i];
            // 查找val在A中应该存放的位置
            int low = 0;
            int high = m+i-1;
            while(low<=high){
                int mid = (low+high)/2;
                if(A[mid]>val){
                    high = mid-1;
                } else {
                    low = mid + 1;
                }
            }
            //此时low>high

            for(int j=m+i-1;j>high;j--){
                A[j+1] = A[j];
            }
            A[high+1] = val;

        }
    }
}