题解 | #字符串的反码#

#include <stdio.h>
#define N 100
int main() {
   char arr[N];
   scanf("%s",arr);
   int i=0;
   while(arr[i]!='\0'){
    if(arr[i]>='a'&&arr[i]<='z'){
        arr[i]='z'-(arr[i]-'a');
    }else if(arr[i]>='A'&&arr[i]<='Z'){
        arr[i]='Z'-(arr[i]-'A');
    }else{
       arr[i]=arr[i];
    }
    i++;
   }
   printf("%s",arr);

}