题解 | #阶乘末尾0的数量#

public class Solution {
    /**
     * the number of 0
     * @param n long长整型 the number
     * @return long长整型
     */
    public long thenumberof0 (long n) {
        // write code here
        //因为一个数的阶乘只有是5或5的倍数乘以2的时候才会出现尾随零
        long sum = 0;
        int k = 5;
        while(n > 0){
            sum += n/k;
            n = n/k;
        }
        return sum;
    }
}