with t as(
select
distinct id,
name,
sum(grade_num) over(partition by user_id) grade_num
from user u
right join grade_info g on u.id=g.user_id
),
t1 as(
select
id,name,grade_num,
dense_rank() over(order by grade_num desc) r
from t
)
select
id,
name,
grade_num
from t1
where r=1

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