题解 | #简单密码#

import sys

dict1 = {1: '1', 2: 'abc', 3: 'def', 4: 'ghi', 5: 'jkl', 6: 'mno', 7: 'pqrs', 8: 'tuv', 9: 'wxyz', 0: '0'}
letters = "abcdefghijklmnopqrstuvwxyza"
for line in sys.stdin:
    a = list(line.rstrip())
    b = ""
    for i in a:
        if i.isdigit():
            b += str(i)
        else:
            found_match = False
            for x, y in dict1.items():
                if i.lower() in y:
                    if i.isupper():
                        i = i.lower()
                        i = letters[letters.index(i) + 1]
                        b += i
                    else:
                        b += str(x)
                    found_match = True
                    break
            if not found_match:
                b += i
    print(b)