题解 | #买房子#

#include <iostream>
#include<math.h>
using namespace std;

int main() {
    int N, SumN;
    float K, SumK;
    // 注意 while 处理多个 case
    while (cin >> N >> K)
    {
        for (int i = 1;; i++)
        {
            bool Flag = false;
            SumN = N * i;
            SumK = 200 * pow((1 + K / 100), i - 1);
            //cout << SumN << "  " << SumK << endl;
            if (SumN > SumK)
            {
                cout << i<<endl;
                Flag = true;
                break;
                return 0;
            }

           if ((SumK - SumN) > (200 - N))
            {
               cout << "Impossible" << endl;
                break;
                return 0;
           
            };
        }
    }
}
// 64 位输出请用 printf("%lld")