题解 | #百钱买百鸡问题#

'''
# 直接遍历查找：x 鸡翁，最多20只；y 鸡母，最多33只；z 鸡稚，最多100.
n=int(input())
for x in range(0,21):
    for y in range(0,33):
        for z in range(0,101):
            if 5*x+3*y+z/3==100 and x+y+z==100:
                print(x,y,z)
'''
'''
# 方程推导：x=4*i  y=25-7i  z=100-x-y
x>=0-----> i>=0
y>=0-----> i<4
故 0<=i<4
'''
while True:
    try:
        n=int(input())
        for i in range(0,4):
            x=4*i
            y=25-7*i
            z=100-x-y
            print(x,y,z)
    except:
        break