题解C++ | #提取不重复的整数#

#include <iostream>
using namespace std;

int main() {
    int n = 0;
    int ns[10] = {0};
    int sum = 0;

    cin >> n;
    while (n > 0)
    {
        int temp = 0;
        temp = n % 10;
        if (ns[temp] == 0) {
            ns[temp] = 1;
            sum = sum * 10 + temp;
        }
        n = n / 10;
    }
    cout << sum;
}
// 64 位输出请用 printf("%lld")