py3 穷解

# -*- coding:utf-8 -*-
class Solution:
    def FindContinuousSequence(self, tsum):
        # write code here
        # tsum小于3的直接不用考虑
        if tsum<3:
            return []
        result = []
        for i in range(1,(tsum+1)/2): # 穷举的话遍历到1/2 即可，本来想用math.ceil的，py2应该跟py3不一样，直接加1就完事了
            tem = []
            count = 0
            while count <tsum:
                tem.append(i)
                count+=i
                i+=1
            if count ==tsum:
                result.append(tem)
        # 使用内置函数进行排序
        result.sort()
        return result