select
university,
difficult_level,
round(count(qpd.question_id) / count(distinct qpd.device_id),4) as avg_answer_cnt
from question_practice_detail as qpd
join user_profile as up
on qpd.device_id=up.device_id
join question_detail as qd
on qpd.question_id=qd.question_id
group by university,difficult_level

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