二维前缀和,思路是建一个二维数组表示从炸到
所能收获的value之和。
然后就一个一个比过去就好了。
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 5e3 + 7;
const ll mod = 1e9 + 7;
inline ll read() {
ll s = 0, f = 1;
char ch;
do {
ch = getchar();
if (ch == '-') f = -1;
} while (ch < 48 || ch > 57);
while (ch >= 48 && ch <= 57)
s = (s << 1) + (s << 3) + (ch ^ 48), ch = getchar();
return s * f;
}
int a[N][N];
int main() {
int n = read(), r = read(), x, y, v, ans = 0;
for (int i = 0; i < n; ++i) x = read(), y = read(), v = read(), a[x+1][y+1] = v;
for (int i = 1; i < N; i++)
for (int j = 1; j < N; j++)
a[i][j] += a[i - 1][j] + a[i][j - 1] - a[i - 1][j - 1];
for (int i = r; i < N; i++)
for (int j = r; j < N; j++)
ans = max(ans, a[i][j] - a[i][j - r] - a[i - r][j] + a[i - r][j - r]);
printf("%d",ans);
return 0;
} 
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