题解 | #简单密码#

• 暴力解法优化：根据小写字母的相对位置（index）获取相应数字

d = "22233344455566677778889999"

def change(s):
    if s.isdigit():
        return s
    if s.isupper() and s != "Z":
        return chr(ord(s) + 1).lower()
    elif s == "Z":
        return "a"
    if "a" <= s <="z":
        return d[ord(s) - ord("a")]

print("".join([change(i) for i in input()]))