WITH
daily_order as (
select
date (order_time) as day,
count(distinct user_id) as order_head
from
order_tb
group by
date (order_time)
),
visit as (
select
date (visit_time) as day,
count(distinct user_id) as visit_head
from
visit_tb
group by
date (visit_time)
)
select
o.day as date,
concat(round(o.order_head/v.visit_head * 100, 1),'%') as cr
from
daily_order o
join visit v on o.day=v.day
order by
o.day asc
- 两个CTE(公用表表达式)之间需要用逗号 , 分隔
- CTE只用写一个WITH,后面可以跟多个表

京公网安备 11010502036488号