题解 | #公共子串计算#

while True:
    try:
        strings1 = input()
        strings2 = input()

        if len(strings1) > len(strings2):
            strings1, strings2 = strings2, strings1

        str_list = []
        for i in range(len(strings1)):
            for j in range(1, len(strings1)+1-i):
                str = strings1[i:i+j]
                if str in strings2 and str not in str_list:
                    str_list.append(str)

        result_list = sorted(str_list, key=lambda x: len(x), reverse=True)
        if result_list:
            result = len(result_list[0])
            print(result)
        else:
            print('0')

    except:
        break