import java.util.Stack;
public class Solution {
Stack<Integer> stack = new Stack<>();
Stack<Integer> minStack = new Stack<>();
public void push(int node) {
stack.push(node);
if(minStack.isEmpty()|| node < minStack.peek()) {
minStack.push(node);
}else {
minStack.push(minStack.peek());
}
}
public void pop() {
stack.pop();
minStack.pop();
}
public int top() {
return stack.peek();
}
public int min() { // 返回栈中最小元素
return minStack.peek();
}
} 我的做法就是新建立一个栈来保存最小值,空间复杂度要加倍。
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