题解 | #对称的二叉树# | Golang

package main
import . "nc_tools"
/*
 * type TreeNode struct {
 *   Val int
 *   Left *TreeNode
 *   Right *TreeNode
 * }
 */

/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 
 * @param pRoot TreeNode类 
 * @return bool布尔型
*/
func isSymmetrical( pRoot *TreeNode ) bool {
    return dfs(pRoot, pRoot)
}

func dfs(one *TreeNode, two * TreeNode) bool {
    if one == nil && two == nil {
        return true
    }
    if one == nil || two == nil {
        return false
    }
    return one.Val == two.Val && dfs(one.Right, two.Left) && dfs(one.Left, two.Right)
}