题解 | 牛的回文编号II

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param x string字符串 
# @return bool布尔型
#
class Solution:
    def isPalindromeNumber(self , x: str) -> bool:
        # write code here
        def huiwen(n):
            return str(n) == str(n)[::-1]

        data = str(x).split(".")
        data0 = data[0]
        data1 = data[1]
       
        index = 0
        for i in range(len(data1) - 1, 0, -1):
            if data1[i] != '0':
                index = i
                break
        data1 = data1[:index + 1]
        print(data1)
        return huiwen(data0) and huiwen(data1)