```SELECT
	c.course_name,
	ROUND( AVG( TIMESTAMPDIFF( MINUTE, in_datetime, out_datetime ) ), 2 ) avg_len 
FROM
	attend_tb a
	LEFT JOIN course_tb c ON a.course_id = c.course_id 
GROUP BY
	c.course_name 
ORDER BY
	avg_len DESC

解题思路:
	每个科目的平均观看时长为每个科目的观看时长平均值。