```SELECT
c.course_name,
ROUND( AVG( TIMESTAMPDIFF( MINUTE, in_datetime, out_datetime ) ), 2 ) avg_len
FROM
attend_tb a
LEFT JOIN course_tb c ON a.course_id = c.course_id
GROUP BY
c.course_name
ORDER BY
avg_len DESC
解题思路:
每个科目的平均观看时长为每个科目的观看时长平均值。