题解 | #字符串的反码#

#include<iostream>
#include<string>
#include<algorithm>
using namespace std;



int main() {
    string str;
    while (cin >> str) {
        for (int i = 0; i < str.size(); i++) {
            char c = str[i];
            if (c >= 'a' && c <= 'z') {
                int distance = c - 'a';
                c = 'z' - distance;
            }
            if (c >= 'A' && c <= 'Z') {
                int distance = c - 'A';
                c = 'Z' - distance;
            }
            cout << c;
        }
        cout << endl;
    };

}